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Showing 1 to 1 of 1 for “"weak*-to-weak continuous operators"”.
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The Pettis Integral and Operator Theory
… finite measure space and X, a Banach space with continuous dual X*. A scalarly measurable function f: Ω→X is Dunford integrable if for each x* X*, x*f L1(µ). Define the operator Tf. X* → L1(µ) by T(x*) = x*f. Then f is Pettis integrable if and only if this operator is weak*-to-weak continuous. …