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Showing 1 to 1 of 1 for “"k-spanning trees"”.
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Generalizations of no k-equal spaces
… between no $k$-equal spaces of $\R$ and $k$-trees of simplicial complexes. It was noticed that the first non-trivial homology group of the $n^{th}$ no $k$-equal space of $\R$ has rank equal to the number of facets in a $k$-dimensional spanning tree of the $n$-dimensional hypercube. We give a …